Case of
Now try another, namely
| > | A:=matrix(2,4,[1,0,1,0,0,1,0,-11]);tvals:=[]; |
| > | fun(A)(1,1); |
| > | seq([t,fun(A)(t,1)],t=1..5); |
| > | tvals:=[op(tvals),3]; |
| > | A1:=ch(A,3,1); |
| > | fun(A1)(1,1); |
| > | seq([t,fun(A1)(1,t)],t=1..5); |
| > | tvals:=[op(tvals),3];A2:=ch(A1,3,2); |
| > | fun(A2)(1,1); |
| > | seq([t,fun(A2)(t,1)],t=1..8); |
| > | tvals:=[op(tvals),6];A3:=ch(A2,6,1); |
| > | fun(A3)(1,1); |
| > | seq([t,fun(A3)(1,t)],t=1..8); |
| > | tvals:=[op(tvals),3];A4:=ch(A3,3,2); |
| > | seq(cat(A,i)=op(cat(A,i)),i=1..4);tvals; |
Note that A2 and A4 have the same second part! So, now we repeat!
| > | unassign('ans11');convert(sqrt(11),confrac,8,ans11); |
| > | ans11; |
| > |
| > |